Finding the mirror image of a line

Published on November 18, 2024

Geometry

The solution finds the equation of a line g' that is the reflection of line g across line s. It involves finding the intersection point of g and s, projecting a direction vector of g onto a normal vector of s, and then calculating the direction vector of g'. Finally, the equation of g' is determined using the intersection point and the direction vector of g'.

Question

Mirror the straight line g on the straight line s and determine the coordinates of the mirror line g'. g: 2x+y-12=0, s: 2x+3y-12=0

Solve in terms of vectors.

Answer

Here’s how to solve this problem using vectors:
1. Find the intersection point of the two lines:
To find the intersection point, we solve the system of equations:

Subtracting the first equation from the second gives , so . Substituting into the first equation gives , so . Therefore, the intersection point is . This point will also lie on the mirrored line g’.
2. Find a direction vector for line g:
We can rewrite the equation of line g in the form . The coefficient of gives us the slope. A direction vector for g is therefore .
3. Find a normal vector for line s:
The coefficients of and in the equation of line s give us a normal vector to s: .
4. Find the projection of onto :
The projection of onto is given by:
5. Find the direction vector of the reflected line g’:
The direction vector of the reflected line, , is given by:
6. Determine the equation of the mirrored line g’:
We have a point on g’ and a direction vector . The parametric equations of g’ are:

Eliminating gives us the Cartesian equation:




Final Answer: The final answer is