Logarithm Equations and Cramer's Rule: Solving Simultaneous Equations
Published on June 7, 2026
Algebra
Learn how to solve logarithm equations and systems of linear equations using Cramer's rule and matrix inverse methods. This guide provides step-by-step solutions.
Question
Solve the question attached
Answer
Based on the image provided, here are the step-by-step solutions for the visible math problems.
QUESTION ONE
a) Solve for
i)
This is a statement to verify or solve. Let’s check if it’s true:
By definition of a logarithm, .
Here, .
The equation is an identity, so it is true for the given base and value.
ii)
Convert the logarithmic equation to exponential form:
Express both sides as powers of :
Since the bases are equal, the exponents must be equal:
iii)
First, use the product rule on the left side:
Move the log term to the left:
Use the product rule again:
Convert to exponential form:
Use the quadratic formula :
Since the argument of a logarithm must be positive ( and ), we must take the positive root:
b) Use Cramer’s rule to solve the following simultaneous equations:
(Note: The image shows , let’s re-read carefully. It looks like )
Let’s re-examine the equations from the image:
Step 1: Find the determinant of the coefficient matrix ():
Expand along the third column:
Step 2: Find (replace first column with constants):
Step 3: Find (replace second column with constants):
Step 4: Find (replace third column with constants):
Solution:
QUESTION TWO
a) Ann, Beth and Martin… share profit in the ratio 7:2:4. Total profit is K7.8m. How much profit does [Ann] get?
Learn how to calculate shopping change, solve a quadratic equation using the quadratic formula, and evaluate fraction operations with clear step-by-step explanations.
Learn how to find the minimum coordinates of the quadratic curve y = x^2 - 10x + 9 by using the method of completing the square to rewrite the equation in vertex form.
Solve |(5x−1)/2| = |(3x+1)/4| by multiplying both sides by 4, then considering equal and opposite expressions inside the absolute values. The solutions are x = 3/7 and x = 1/13.
Learn how to prove that the real part of the complex expression (z+1)/(z-1) is equal to zero when |z|=1 and z is not equal to 1, using complex conjugates and magnitude properties.