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Find the equation of the tangent line to a circle at a given point.
Published on March 2, 2025
Geometry
The equation of the tangent line to the circle (x-3)^2 + (y-2)^2 = 25 at the point (-1, 5) is 4x - 3y + 19 = 0.
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Solve 38
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Published on March 2, 2025
The equation of the tangent line to the circle (x-3)^2 + (y-2)^2 = 25 at the point (-1, 5) is 4x - 3y + 19 = 0.
Solve 38
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