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Solve a system of four linear equations in four variables
Published on December 7, 2024
Algebra
The solution to the system of linear equations is x = 1, y = -2, z = 3, and w = 2.
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Published on December 7, 2024
The solution to the system of linear equations is x = 1, y = -2, z = 3, and w = 2.
Given a^2 - 4 = 0, the possible values for a are 2 and -2. Substituting these values into a^3 - 4, we find that a^3 - 4 can be either 4 or -12.
The equation represents an ellipse centered at (-2, 0) with a vertical major axis of length 4 and a horizontal minor axis of length 2.
The solution to the equation \sqrt{(X - 4)(X + 4)} = 3 is X = 5 and X = -5.
The solution involves finding the values of a and b, given a*a = 8 and a*b = 24. Then, b*b is calculated, resulting in a final answer of 72.
Cramer's rule is used to solve a system of four linear equations with four unknowns, resulting in the values of x1, x2, x3, and x4.
The square root of 19 squared plus 19 plus 20 is calculated to be 20.
To find (a+b)^2, given a^2 + b^2 = 29 and ab = 10, substitute the given values into the equation (a+b)^2 = a^2 + 2ab + b^2, resulting in (a+b)^2 = 49.
The only real solution to the cubic equation a^3 + a^2 - 36 = 0 is a = 3.
The solution to the equation X^3 - X^0 = 26 is X = 3.
The equation (x-1)^(|x|-4) = 1 has solutions x = -4, 0, 2, and 4.