Calculus Integration Problems: Indefinite and Definite Integrals

Published on March 22, 2026

Calculus

Solution to three problems involving calculus techniques: basic indefinite integration, u-substitution for powers, and integration by parts for logarithms.

Question

please answer with detail

Answer

Here are the step-by-step solutions for the given integration problems.

a. Evaluate the following indefinite integral: (5 points)

Step 1: Separate the integral using the linearity property.
Step 2: Evaluate the first integral, .
We use -substitution. Let .
Then , which means .
Step 3: Evaluate the second integral, .
We use -substitution. Let .
Then , which means .
Step 4: Combine the results.
Let .

b. Evaluate the following indefinite integral: (10 points)

Step 1: Use -substitution.
Notice that the derivative of the term inside the parentheses, , is . This suggests a -substitution.
Let .
Then .
We need , so we solve for it:
Step 2: Substitute into the integral.
Step 3: Evaluate the integral with respect to .
Using the power rule for integration ( for ):
Step 4: Substitute back .

c. Evaluate the following definite integral: (10 points)

Step 1: Use Integration by Parts.
The formula for integration by parts is .
We choose such that its derivative simplifies and such that it can be easily integrated. For , we usually choose it as .
Let and .
Then and .
Step 2: Apply the integration by parts formula.
Step 3: Evaluate the first term (the boundary term).
Since and :
Step 4: Evaluate the remaining integral.
Step 5: Combine the results.
To combine these, find a common denominator (9):

Final Answers:

a.
b.
c.